document.write( "Question 1007049: Mary has $3,500 in a savings account earning 4 1/2% annual interest that is compounded continuously. How much will be in the account at the end of 3 years? \n" ); document.write( "
Algebra.Com's Answer #854450 by ikleyn(53875)\"\" \"About 
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\n" ); document.write( "Mary has $3,500 in a savings account earning 4 1/2% annual interest that is compounded continuously.
\n" ); document.write( "How much will be in the account at the end of 3 years?
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\n" ); document.write( "\n" ); document.write( "        Calculations in the post by @lwsshak3 are incorrect and lead to wrong answer.\r
\n" ); document.write( "\n" ); document.write( "        I came to bring a correct solution.\r
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\n" ); document.write( "\n" ); document.write( "Formula for continuous compounding: A = \"Pe%5E%28rt%29\",
\n" ); document.write( "where P is initial investment, r is the interest rate, A is the amount after t years.\r
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\n" ); document.write( "\n" ); document.write( "A = \"3500%2A2.71828%5E%280.045%2A3%29\" = $4005.88, to the last cent.         ANSWER\r
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\n" ); document.write( "\n" ); document.write( "Solved correctly.\r
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