document.write( "Question 1161528: A boy throws a stone from the top of a building 46.0 m above ground. The
\n" ); document.write( "stone is thrown at an angle of 33.0° below the horizontal and strikes the
\n" ); document.write( "ground 55.6 m away from the building, find the following: (a) Time of flight.
\n" ); document.write( "(b) Initial speed. (c) The magnitude and the direction of the velocity of the
\n" ); document.write( "stone just before it strikes the ground.
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Algebra.Com's Answer #854443 by KMST(5377)\"\" \"About 
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EDITED for clarity and to correct multiple typos on April 28, 2026:
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\n" ); document.write( "This is really a Physics class problem,
\n" ); document.write( "but from the math point of view it involves algebra, vectors, geometry and trigonometry.
\n" ); document.write( "Times will be in seconds from the time the stone left the boy's hand,
\n" ); document.write( "distances will be in meters,
\n" ); document.write( "speeds will be in m/s, and accelerations in m/s/s,
\n" ); document.write( "with the units understood, but not always stated.
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\n" ); document.write( "\"v\"\"%22=%22\" initial speed (magnitude of the velocity) of the stone as it leaves the boy's hand
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\n" ); document.write( "\"v%5Bh%5D=v%2Acos33%5Eo\"\"%22=%22\" magnitude of the horizontal vector component of that initial velocity
\n" ); document.write( "\"v%5Bd%5D=v%2Asin33%5Eo\"\"%22=%22\" magnitude of the vertical, downward vector component of that initial velocity
\n" ); document.write( "\"T\"\"%22=%22\" Time of flight of the stone, in seconds
\n" ); document.write( "We reasonably assume that the effects of air friction or wind do not cause a measurable difference in the motion of the stone,
\n" ); document.write( "so that the horizontal velocity is constant,
\n" ); document.write( "and the vertical velocity is only affected by gravity.
\n" ); document.write( "We know that latitude and altitude affect the acceleration of an object due to gravity,
\n" ); document.write( "but not having precise location data, we will use the value of 9.8m/s/s.
\n" ); document.write( "The downward velocity will increase linearly with \"t\" ,
\n" ); document.write( "the time in seconds \"t\" since the stone was thrown,
\n" ); document.write( "as \"v%2Asin33%5Eo%2B9.8t\"
\n" ); document.write( "from \"v%2Asin33%5Eo\" at \"t=0\" to \"v%2Asin33%5Eo%2B9.8T\" at \"t=T\" .
\n" ); document.write( "The average downward velocity during that time will be the average of initial and final velocities:
\n" ); document.write( "\"%281%2F2%29%28v%2Asin33%5Eo%2Bv%2Asin33%5Eo%2B9.8T%29=v%2Asin33%5Eo%2B4.9T\"
\n" ); document.write( "The horizontal and vertical distances traveled by the stone (in meters) will be
\n" ); document.write( "\"highlight%28v%2Acos33%5Eo%2AT=55.6%29\" and
\n" ); document.write( "\"%28v%2Asin33%5Eo%2B4.9T%29T=46%29\"-->\"highlight%28v%2AT%2Asin33%5Eo%2B4.9T%5E2=46%29\"
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\n" ); document.write( "Part (a) and part (b):
\n" ); document.write( "We can find \"v\" and \"T\" from the equations above.
\n" ); document.write( "From the first of the highlighted equations above, we get \"v%2AT=55.6%281%2Fcos33%5Eo%29\" ,
\n" ); document.write( "and substituting the expression found for \"v%2AT\" into the second equation, we get
\n" ); document.write( "\"55.6%281%2Fcos33%5Eo%29%2Asin33%5Eo%2B4.9T%5E2=46\"-->\"55.6%28sin33%5Eo%2Fcos33%5Eo%29%2B4.9T%5E2=46\"-->\"55.6%2Atan33%5Eo%2B4.9T%5E2=46\"
\n" ); document.write( "Using \"tan33%5Eo=0.64941\" (rounded) , we substitute to get
\n" ); document.write( "\"55.6%2A0.64941%2B4.9T%5E2=46\"-->\"T%5E2=%2846-55.6%2A0.64941%29%2F4.9=2.0189\" (rounded), and \"T=sqrt%282.0189%29\" --> \"highlight%28T=1.42%29\" (rounded).
\n" ); document.write( "Answer for part (a): The stone flies for \"highlight%28T=1.42seconds%29\" .
\n" ); document.write( "Then, substituting the value found above and \"cos33%5Eo=0.83867\" into \"highlight%28v%2Acos33%5Eo%2AT=55.6%29\" , we get
\n" ); document.write( "\"v%2A0.83867%2A1.42=55.6\"-->\"v=55.6%2F1.42%2F0.83867\" --> \"highlight%28v=46.7%29\" (rounded).
\n" ); document.write( "The initial speed (magnitude of the initial velocity) of the stone was \"46.7\" m/s.
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\n" ); document.write( "Part(c):
\n" ); document.write( "For the stone, the time \"just before it strikes the ground\" is a minuscule fraction of a second before t=1.42 seconds, which rounds to \"T=1.42seconds\"
\n" ); document.write( "We can calculate the magnitude and the direction of the velocity of the
\n" ); document.write( "stone at that time from the magnitude of its horizontal and downward components.
\n" ); document.write( "As stated early,
\n" ); document.write( "the horizontal component of the stone velocity is constant, with magnitude \"v%5Bh%5D=v%2Acos33%5Eo\" ,
\n" ); document.write( "while the vertical component is a function of the time \"t\" , in seconds, since the stone was thrown.
\n" ); document.write( "It was also established that at time \"T=1.42seconds\" , the downwards velocity was \"V%5Bd%5D=v%2Asin33%5Eo%2B9.8T\" ,
\n" ); document.write( "Substituting \"cos33%5Eo=0.83867\" , \"sin33%5Eo=0.54464\" ,
\n" ); document.write( "and the already found values \"T=1.42\" and \"v=46.7\" , we get that
\n" ); document.write( "\"v%5Bh%5D=46.7%2A0.83867=39.17\" and \"V%5Bd%5D=46.7%2A0.54464%5Eo%2B9.8%2A1.42=39.35\"
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\n" ); document.write( "Adding those horizontal and vertical components vectors,
\n" ); document.write( "we calculate the magnitude of the velocity vector at 1.42 second as
\n" ); document.write( "\"V=sqrt%2839.17%5E2%2B39.35%5E2%29\" --> \"highlight%28V=67.9%29\"
\n" ); document.write( "We can calculate its direction as the angle \"theta\" below the horizontal from
\n" ); document.write( "\"tan%28theta%29=39.35%2F39.17=1.0046\" (rounded), which corresponds to
\n" ); document.write( "\"highlight%28theta=45.1%5Eo%29\" .
\n" ); document.write( "The calculated magnitude and direction of the velocity of the
\n" ); document.write( "stone just before it strikes the ground is \"highlight%2867.9%29\"m/s at an angle below the horizontal of \"highlight%2845.1%5Eo%29\" .
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