document.write( "Question 1210613: Marek and Zaven had 900 coins altogether. Marek spent 25% fewer coins than Zaven. Zaven was left with 50% as many coins as the number he spent. Marek had 75% of the total number of coins the two friends had left in the end. How many coins did Marek have in the end?
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Algebra.Com's Answer #854419 by math_tutor2020(3837)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "I'd go with the last method tutor KMST mentioned.
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ZavenMarekTotal
Start3x900-3x900
Spent2x1.5x3.5x
Finalx900-4.5x900-3.5x
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\n" ); document.write( "\n" ); document.write( "Refer to the given statement that
\"Marek had 75% of the total number of coins the two friends had left in the end\"
which means we'll use the last two entries of the bottom row to form this equation
\n" ); document.write( "900-4.5x = 0.75*(900-3.5x)
\n" ); document.write( "That equation solves to x = 120\r
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\n" ); document.write( "\n" ); document.write( "Plugging that value of x back into the table above produces the following:
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ZavenMarekTotal
Start360540900
Spent240180420
Final120360480
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\n" ); document.write( "\n" ); document.write( "Answer: 360 coins
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