document.write( "Question 1210613: Marek and Zaven had 900 coins altogether. Marek spent 25% fewer coins than Zaven. Zaven was left with 50% as many coins as the number he spent. Marek had 75% of the total number of coins the two friends had left in the end. How many coins did Marek have in the end?
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Algebra.Com's Answer #854416 by KMST(5362) You can put this solution on YOUR website! DATA WE HAVE: \n" ); document.write( "Marek and Zaven had 900 coins altogether. \n" ); document.write( "That is what they had initially. \n" ); document.write( " \n" ); document.write( "Zaven was left with 50% (half) as many coins as the number he spent. \n" ); document.write( "He spent twice as many coins as he was left with. \n" ); document.write( "For every 1 coin he had left, there were 2 he had spent, and 3 that he originally had. \n" ); document.write( "That tells me that the number of coins Zaven initially had was a multiple of 3. \n" ); document.write( " \n" ); document.write( "Marek spent 25% fewer coins than Zaven. \n" ); document.write( "Marek spent 100%-25%=75% of what Zaven spent. \n" ); document.write( "If I knew how much Zaven spent I can multiply times 0.75 to find what Marek spent. \n" ); document.write( "For every 4 coins Zaven spent Marek spent 3. So I could instead divide by 4 and multiply times 3. \n" ); document.write( " \n" ); document.write( "Marek had 75% of the total number of coins the two friends had left in the end. \n" ); document.write( " \n" ); document.write( "Could Marek have initially had 75% of the total number of coins the two friends had left in the end? It does not seem possible. \n" ); document.write( "I think what the \"in the end\" part applies to the whole sentence, and what was meant is: \n" ); document.write( "In the end, Marek had 75% of the total number of coins the two friends had left. \n" ); document.write( " \n" ); document.write( "AN EASY WAY TO SOLVE IT (guess and check): \n" ); document.write( " \n" ); document.write( "Fist Guess: \n" ); document.write( "What if Zaven initially had \n" ); document.write( "Then, Zaven must have spent \n" ); document.write( "and must have had left with \n" ); document.write( "Then, Marek \n" ); document.write( "must have started with \n" ); document.write( "must have spent \n" ); document.write( "and have had left \n" ); document.write( "Then, Zaven and Marek then together had \n" ); document.write( "and that would mean that in the end, \n" ); document.write( "the number of coins Marek had, \n" ); document.write( "as a fraction and as a percentage of the number of coins Zaven and Marek had together, was \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "We need \n" ); document.write( " \n" ); document.write( "second Guess: \n" ); document.write( "What if Zaven initially had \n" ); document.write( "Then, Zaven must have spent \n" ); document.write( "and must have had left with \n" ); document.write( "Then, Marek \n" ); document.write( "must have started with \n" ); document.write( "must have spent \n" ); document.write( "and have had left \n" ); document.write( "Then, Zaven and Marek then together had \n" ); document.write( "and that would mean that in the end, \n" ); document.write( "the number of coins Marek had, \n" ); document.write( "as a fraction and as a percentage of the number of coins Zaven and Marek had together, was \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "A HYBRID OF THE SOLUTION ABOVE AND jogsarithmetic's solution: \n" ); document.write( "Let's call the number of coins Zaven had at start, what he spent, and what he had left in the end 3x, 2x, and x, respectively. \n" ); document.write( " \n" ); document.write( "Then, we have just one variable, and the equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "In th e end, the number of coins Marek had was \n" ); document.write( " \n" ); document.write( "Some teachers want problems solved the way it was taught in class, and may not like alternative solutions. \n" ); document.write( "Some teacher may want to give extra point f=if more that one way to solve the problem is shown. \n" ); document.write( " |