document.write( "Question 1210613: Marek and Zaven had 900 coins altogether. Marek spent 25% fewer coins than Zaven. Zaven was left with 50% as many coins as the number he spent. Marek had 75% of the total number of coins the two friends had left in the end. How many coins did Marek have in the end?
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Algebra.Com's Answer #854415 by josgarithmetic(39818)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "             Marek             Zaven          TOTAL\r\n" );
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document.write( "Start        900-z               z             900\r\n" );
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document.write( "AFTER\r\n" );
document.write( "SPENT       900-z-0.75x         z-x=0.5x\r\n" );
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document.write( "            900-z-0.75x=(0.75)(900-z-0.75x+0.5x)\r\n" );
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\n" ); document.write( "That does not go directly to the quanity asked in the question. \r
\n" ); document.write( "\n" ); document.write( "System is \"system%28z-x=0.5x%2C900-z-0.75x=0.75%28900-z-0.25x%29%29\"
\n" ); document.write( "But a more efficient setup may be possible.\r
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\n" ); document.write( "\n" ); document.write( "(*WARNING: possible fault in setup; algebraic steps produced faulty outcome)
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