document.write( "Question 1210612: Fill in the blanks to make an equation that is linear in disguise, and has a solution.
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document.write( "sqrt(2x - 3) + __x + ___ = ___x - ___ + ____
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document.write( "8 9 10 11 12 13 14 15 16 17 18 19 20 \n" );
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Algebra.Com's Answer #854413 by greenestamps(13351) You can put this solution on YOUR website! \n" ); document.write( "It is not at all clear what the purpose of this problem is. You can find numerous solutions either by pure trial and error or using formal algebra. \n" ); document.write( "And, as another tutor pointed out, it is not clear whether numbers from the given list can be used more than once. \n" ); document.write( "Using A, B, C, D, and E to represent the numbers in the blanks, the given equation is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This equation can be \"linear in disguise\" if x is any number for which \n" ); document.write( "Even limiting ourselves to integer perfect squares, there are an infinite number of possible values for x: \r\n" ); document.write( "\r\n" ); document.write( " 2x-3 x\r\n" ); document.write( " ----------\r\n" ); document.write( " 0 3/2\r\n" ); document.write( " 1 2\r\n" ); document.write( " 9 6\r\n" ); document.write( " 25 14\r\n" ); document.write( " 49 26\r\n" ); document.write( " ... \n" ); document.write( "For many of those values of x the equation will have solutions (often multiple solutions) with A, B, C, D, and E being values from the given list. \n" ); document.write( "But \n" ); document.write( "Finally \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Squaring both sides will yield a quadratic equation; since we are supposed to get a linear equation, it would be necessary for \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |