document.write( "Question 1210612: Fill in the blanks to make an equation that is linear in disguise, and has a solution.
\n" ); document.write( "sqrt(2x - 3) + __x + ___ = ___x - ___ + ____
\n" ); document.write( "8 9 10 11 12 13 14 15 16 17 18 19 20
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Algebra.Com's Answer #854413 by greenestamps(13351)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "It is not at all clear what the purpose of this problem is. You can find numerous solutions either by pure trial and error or using formal algebra.

\n" ); document.write( "And, as another tutor pointed out, it is not clear whether numbers from the given list can be used more than once.

\n" ); document.write( "Using A, B, C, D, and E to represent the numbers in the blanks, the given equation is

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\n" ); document.write( "\"sqrt%282x-3%29%2BAx%2BB=Cx-D%2BE\"

\n" ); document.write( "This equation can be \"linear in disguise\" if x is any number for which \"2x-3\" is a perfect square.

\n" ); document.write( "Even limiting ourselves to integer perfect squares, there are an infinite number of possible values for x:
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document.write( "    2x-3   x\r\n" );
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document.write( "     0    3/2\r\n" );
document.write( "     1      2\r\n" );
document.write( "     9      6\r\n" );
document.write( "    25     14\r\n" );
document.write( "    49     26\r\n" );
document.write( "    ...

\n" ); document.write( "For many of those values of x the equation will have solutions (often multiple solutions) with A, B, C, D, and E being values from the given list.

\n" ); document.write( "But \"2x-3\" can be a perfect square which is not an integer; that will lead us to a whole new family of possible values for x, and possibly many of those will allow additional solutions to the problem.

\n" ); document.write( "Finally \"2x-3\" does not have to be a perfect square. We can isolate the radical and square both sides of the equation to get yet another whole family of possible solutions to the problem.

\n" ); document.write( "\"sqrt%282x-3%29=Cx-D%2BE-Ax-B\"
\n" ); document.write( "\"sqrt%282x-3%29=%28C-A%29x%2B%28-D%2BE-B%29\"

\n" ); document.write( "Squaring both sides will yield a quadratic equation; since we are supposed to get a linear equation, it would be necessary for \"C-A\" to be zero -- i.e., A and C would have to be the same value from the given list. If that is indeed allowed, then we open up the possibility of many more solutions to the problem.
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