document.write( "Question 1162408: The mean length of a small counterbalance bar is 43 millimeters. The production supervisor
\n" ); document.write( "is concerned that the adjustments of the machine producing the bar have changed. He asks
\n" ); document.write( "the engineering to investigate. Engineering selects a random sample of 30 bars and measure
\n" ); document.write( "each. The results are reported below in millimeters.
\n" ); document.write( "42 39 42 45 43 40 39 41 40 42
\n" ); document.write( "43 42 45 47 38 46 48 42 47 41
\n" ); document.write( "40 44 43 42 40 41 42 39 40 41
\n" ); document.write( "Is it reasonable to conclude that the mean length of the bars reduced?
\n" ); document.write( "

Algebra.Com's Answer #854405 by CPhill(2264)\"\" \"About 
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```python?code_reference&code_event_index=3
\n" ); document.write( "import numpy as np
\n" ); document.write( "from scipy import stats\r
\n" ); document.write( "\n" ); document.write( "data = [
\n" ); document.write( " 42, 39, 42, 45, 43, 40, 39, 41, 40, 42,
\n" ); document.write( " 43, 42, 45, 47, 38, 46, 48, 42, 47, 41,
\n" ); document.write( " 40, 44, 43, 42, 40, 41, 42, 39, 40, 41
\n" ); document.write( "]\r
\n" ); document.write( "\n" ); document.write( "mu_0 = 43
\n" ); document.write( "n = len(data)
\n" ); document.write( "x_bar = np.mean(data)
\n" ); document.write( "s = np.std(data, ddof=1)
\n" ); document.write( "se = s / np.sqrt(n)
\n" ); document.write( "t_stat = (x_bar - mu_0) / se
\n" ); document.write( "df = n - 1\r
\n" ); document.write( "\n" ); document.write( "# One-tailed test (Reduced mean: HA: mu < 43)
\n" ); document.write( "p_value = stats.t.cdf(t_stat, df)\r
\n" ); document.write( "\n" ); document.write( "print(f\"{x_bar=}\")
\n" ); document.write( "print(f\"{s=}\")
\n" ); document.write( "print(f\"{t_stat=}\")
\n" ); document.write( "print(f\"{p_value=}\")\r
\n" ); document.write( "\n" ); document.write( "```
\n" ); document.write( "```text?code_stdout&code_event_index=3
\n" ); document.write( "x_bar=42.13333333333333
\n" ); document.write( "s=2.582879085016581
\n" ); document.write( "t_stat=-1.8378440010020713
\n" ); document.write( "p_value=0.038175278168928364\r
\n" ); document.write( "\n" ); document.write( "```
\n" ); document.write( "To determine if the mean length of the bars has reduced, we conduct a **one-sample t-test**.\r
\n" ); document.write( "\n" ); document.write( "### 1. State the Hypotheses
\n" ); document.write( "* **Null Hypothesis ($H_0$):** $\mu \geq 43$ (The mean length has not reduced)
\n" ); document.write( "* **Alternative Hypothesis ($H_A$):** $\mu < 43$ (The mean length has reduced)\r
\n" ); document.write( "\n" ); document.write( "### 2. Identify Sample Statistics
\n" ); document.write( "From the provided data of $n = 30$ bars:
\n" ); document.write( "* **Sample Mean ($\bar{x}$):** $42.13$ mm
\n" ); document.write( "* **Sample Standard Deviation ($s$):** $2.58$ mm
\n" ); document.write( "* **Hypothesized Mean ($\mu_0$):** $43$ mm\r
\n" ); document.write( "\n" ); document.write( "### 3. Calculate the Test Statistic ($t$)
\n" ); document.write( "The $t$-statistic measures how many standard errors the sample mean is from the hypothesized mean:
\n" ); document.write( "$$t = \frac{\bar{x} - \mu_0}{s / \sqrt{n}} = \frac{42.13 - 43}{2.58 / \sqrt{30}} \approx -1.838$$\r
\n" ); document.write( "\n" ); document.write( "### 4. Determine the p-value
\n" ); document.write( "Using the $t$-distribution with $df = n - 1 = 29$:
\n" ); document.write( "* **$p$-value:** $\approx 0.0382$\r
\n" ); document.write( "\n" ); document.write( "### 5. Conclusion
\n" ); document.write( "At a standard significance level of **$\alpha = 0.05$**:
\n" ); document.write( "* Since the $p$-value ($0.0382$) is **less than** $0.05$, we **reject the null hypothesis**.\r
\n" ); document.write( "\n" ); document.write( "**Final Result:** Yes, it is **reasonable to conclude** that the mean length of the bars has reduced. The statistical evidence indicates that the decrease from $43$ mm to $42.13$ mm is significant enough that it is unlikely to have occurred by random chance alone. \r
\n" ); document.write( "\n" ); document.write( "> **Note:** If a more stringent significance level like $\alpha = 0.01$ were used, we would fail to reject the null hypothesis, as $0.0382 > 0.01$. However, in most industrial engineering contexts, $0.05$ is the standard threshold for investigation.
\n" ); document.write( "
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