document.write( "Question 1164606: Write a piecewise function for the given situation.\r
\n" );
document.write( "\n" );
document.write( "A parking garage charges $2 an hour for parking in the garage with a maximum amount of money you can be charged is $16 no matter the amount time you parked there. \n" );
document.write( "
Algebra.Com's Answer #854343 by CPhill(2264) You can put this solution on YOUR website! To write this piecewise function, we define the cost $C$ based on the number of hours $t$ spent in the garage.\r \n" ); document.write( "\n" ); document.write( "### **1. Identify the Conditions** \n" ); document.write( "* **The Hourly Rate:** The garage charges **$2$** per hour. This is represented by $2t$. \n" ); document.write( "* **The Maximum Cap:** Once the cost reaches **$16$**, the price stops increasing. \n" ); document.write( "* **The \"Switch\" Point:** To find when the cap kicks in, we solve $2t = 16$. This happens at **$t = 8$** hours.\r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "### **2. The Piecewise Function**\r \n" ); document.write( "\n" ); document.write( "Let $C(t)$ be the total cost in dollars and $t$ be the time in hours ($t \ge 0$):\r \n" ); document.write( "\n" ); document.write( "$$C(t) = \n" ); document.write( "\begin{cases} \n" ); document.write( "2t & 0 \le t < 8 \\ \n" ); document.write( "16 & t \ge 8 \n" ); document.write( "\end{cases}$$\r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "### **3. Breakdown of the Function** \n" ); document.write( "* **$2t$ for $0 \le t < 8$:** If you stay for less than 8 hours, you pay exactly \$2 for every hour parked. For example, 3 hours costs \$6. \n" ); document.write( "* **$16$ for $t \ge 8$:** Once you hit the 8-hour mark, the \"flat rate\" applies. Whether you stay for 9 hours, 12 hours, or 24 hours, the price remains stuck at \$16.\r \n" ); document.write( "\n" ); document.write( "### **Quick Check** \n" ); document.write( "If you stay for **5 hours**: $C(5) = 2(5) = \$10$. \n" ); document.write( "If you stay for **10 hours**: $C(10) = \$16$ (since $10 > 8$).\r \n" ); document.write( "\n" ); document.write( "Does your specific parking problem require you to account for partial hours (like rounding up to the next hour), or is it strictly linear? \n" ); document.write( " |