document.write( "Question 1164609: Given the following logical expression, place the operations in the order in which you would apply, from first operation to last.\r
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document.write( "~p ∧ q → r \n" );
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Algebra.Com's Answer #854341 by CPhill(2264) You can put this solution on YOUR website! Following the standard rules of **Logical Precedence**, we evaluate the operations from the most \"tightly bound\" operator to the \"main connective.\" \r \n" ); document.write( "\n" ); document.write( "The hierarchy is as follows: \n" ); document.write( "1. **Negation** ($\sim$) \n" ); document.write( "2. **Conjunction** ($\land$) \n" ); document.write( "3. **Disjunction** ($\lor$) \n" ); document.write( "4. **Conditional** ($\to$)\r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "### **Order of Application**\r \n" ); document.write( "\n" ); document.write( "For the expression **$\sim p \land q \to r$**, the operations should be applied in this order:\r \n" ); document.write( "\n" ); document.write( "1. **First: Negation ($\sim p$)** \n" ); document.write( " The \"NOT\" operator is applied only to the variable immediately following it. You must flip the truth value of $p$ first. \n" ); document.write( "2. **Second: Conjunction ($\sim p \land q$)** \n" ); document.write( " The \"AND\" operator takes precedence over the conditional. You evaluate the relationship between the result of Step 1 and $q$. \n" ); document.write( "3. **Last: Conditional ($\dots \to r$)** \n" ); document.write( " The \"IF...THEN\" operator is the main connective here. It evaluates the relationship between the entire left-hand side (the antecedent) and $r$ (the consequent).\r \n" ); document.write( "\n" ); document.write( "### **Summary Table** \n" ); document.write( "| Order | Operation | Symbol | Resulting Grouping | \n" ); document.write( "| :--- | :--- | :--- | :--- | \n" ); document.write( "| **1st** | Negation | $\sim$ | $(\sim p)$ | \n" ); document.write( "| **2nd** | Conjunction | $\land$ | $(\sim p \land q)$ | \n" ); document.write( "| **3rd** | Conditional | $\to$ | $((\sim p \land q) \to r)$ |\r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "**Wait, why not the arrow first?** \n" ); document.write( "In logic, the conditional ($\to$) is considered \"weaker\" than conjunction or negation. If you wanted the arrow to be evaluated first, the expression would have required parentheses like this: $\sim p \land (q \to r)$. Without them, we follow the hierarchy above.\r \n" ); document.write( "\n" ); document.write( "Are you working on a truth table for this specific statement? \n" ); document.write( " |