document.write( "Question 117422: show graph one soulution, no solution or many solutions\r
\n" ); document.write( "\n" ); document.write( "x + y =-3
\n" ); document.write( "2x-y= -3
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Algebra.Com's Answer #85434 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solve the System of Equations by Graphing

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\n" ); document.write( " Start with the given system of equations:
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\n" ); document.write( " \"1x%2By=-3\"
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\n" ); document.write( " \"2x-y=-3\"
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\n" ); document.write( " In order to graph these equations, we need to solve for y for each equation.
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\n" ); document.write( " So let's solve for y on the first equation
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\n" ); document.write( " \"1x%2By=-3\" Start with the given equation
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\n" ); document.write( " \"1y=-3-x\" Subtract \"+x\" from both sides
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\n" ); document.write( " \"1y=-x-3\" Rearrange the equation
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\n" ); document.write( " \"y=%28-x-3%29%2F%281%29\" Divide both sides by \"1\"
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\n" ); document.write( " \"y=%28-1%2F1%29x%2B%28-3%29%2F%281%29\" Break up the fraction
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\n" ); document.write( " \"y=-x-3\" Reduce
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\n" ); document.write( " Now lets graph \"y=-x-3\" (note: if you need help with graphing, check out this solver)
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\n" ); document.write( " \"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+-x-3%29+\" Graph of \"y=-x-3\"
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\n" ); document.write( " So let's solve for y on the second equation
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\n" ); document.write( " \"2x-y=-3\" Start with the given equation
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\n" ); document.write( " \"-y=-3-2x\" Subtract \"2+x\" from both sides
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\n" ); document.write( " \"-y=-2x-3\" Rearrange the equation
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\n" ); document.write( " \"y=%28-2x-3%29%2F%28-1%29\" Divide both sides by \"-1\"
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\n" ); document.write( " \"y=%28-2%2F-1%29x%2B%28-3%29%2F%28-1%29\" Break up the fraction
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\n" ); document.write( " \"y=2x%2B3\" Reduce
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\n" ); document.write( " Now lets add the graph of \"y=2x%2B3\" to our first plot to get:
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\n" ); document.write( " \"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+-x-3%2C2x%2B3%29+\" Graph of \"y=-x-3\"(red) and \"y=2x%2B3\"(green)
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\n" ); document.write( " From the graph, we can see that the two lines intersect at the point (\"-2\",\"-1\") (note: you might have to adjust the window to see the intersection)
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