document.write( "Question 22105: River flows at 2 mph. Phil can paddle in still water at 8 mph. If he is 4 miles downstream from a log floating toward him,
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document.write( "how long will it take him to reach the log? \n" );
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Algebra.Com's Answer #854324 by math_tutor2020(3837) ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: 1/2 of an hour or 30 minutes\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's say the river flows south. \n" ); document.write( "Define points A, B, and C such that: \n" ); document.write( "A = log's starting location \n" ); document.write( "B = Phil's starting location \n" ); document.write( "C = point in between A and B where Phil reaches the log \n" ); document.write( " \n" ); document.write( "The diagram is optional but could be handy.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Phil's speed is 8 mph in still water. \n" ); document.write( "But since Phil has to swim upstream against the 2 mph current, it slows him down to 8-2 = 6 mph. \n" ); document.write( "So he travels 6x miles where x is the length of time in hours. \n" ); document.write( "I'm using the formula: distance = rate*timeMeanwhile, the log travels at 2 mph for the same amount of time x. \n" ); document.write( "It travels 2x miles.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To recap so far we have these distances \n" ); document.write( "AC = 2x \n" ); document.write( "BC = 6x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "These two distance subtotals must add to the 4 mile gap between the points A and B. \n" ); document.write( "AC+BC = AB \n" ); document.write( "2x+6x = AB \n" ); document.write( "2x+6x = 4 \n" ); document.write( "8x = 4 \n" ); document.write( "x = 4/8 \n" ); document.write( "x = 1/2 of an hour aka 30 minutes \n" ); document.write( " \n" ); document.write( " |