document.write( "Question 63744: Please help me solve this problem\r
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Algebra.Com's Answer #854317 by MathTherapy(10849)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Please help me solve this problem\r\n" );
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document.write( "Solve the inequality\r\n" );
document.write( "3x^2-2x-1>- (greater than or equal) 0\r\n" );
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document.write( "@praseenakos@yahoo.com's attempt at a \"SOLUTION\" is MOSTLY WRONG, as:\r\n" );
document.write( "1) The quadratic \"3x%5E2+-+2x+-+1+%3E=+0\" doesn't need to be solved using the quadratic formula, as it can be factorized\r\n" );
document.write( "2) One of the solutions to the quadratic is NOT \"-+1%2F6\", but \"-+1%2F3\". instead\r\n" );
document.write( "3) The positive solution, \"x+%3E=+1\" is part of the other solution, \"x+%3E=+-+1%2F3\". So, ordinarily, you CAN'T have both.\r\n" );
document.write( "4) Solutions to INEQUALITIES are different from solutions to EQUATIONS. Inequalities' solutions need to\r\n" );
document.write( "     be determined based on their CRITICAL POINTS' ranges.\r\n" );
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document.write( "     As such, IGNORE @praseenakos@yahoo.com's \"SOLUTIONS,\" and ACCEPT the SOLUTION-SETS by Tutor @rahman(247)\r\n" );
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document.write( "The most concise explanation for the solutions?:\r\n" );
document.write( "Solutions. \"x+=+-+1%2F3\" and x = 1 mean that there're 2 CRITICAL POINTS, \"-+1%2F3\" and 1.\r\n" );
document.write( "The solutions will be the RANGES OUTSIDE these 2 critical points, including the critical points.\r\n" );
document.write( "So, for \"x+=+-+1%2F3\", the solution set will be the range to the LEFT of \"-+1%2F3\", and \"-+1%2F3\", itself, or: \"x+%3C=+-+1%2F3\"\r\n" );
document.write( "And, for x = 1, the solution set will be the range to the RIGHT of 1, and 1, or \"x+%3E=+1\".
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