\r\n" );
document.write( "Please help me solve this problem\r\n" );
document.write( "\r\n" );
document.write( "Solve the inequality\r\n" );
document.write( "3x^2-2x-1>- (greater than or equal) 0\r\n" );
document.write( "*************************************\r\n" );
document.write( "@praseenakos@yahoo.com's attempt at a \"SOLUTION\" is MOSTLY WRONG, as:\r\n" );
document.write( "1) The quadratic
doesn't need to be solved using the quadratic formula, as it can be factorized\r\n" );
document.write( "2) One of the solutions to the quadratic is NOT
, but
. instead\r\n" );
document.write( "3) The positive solution,
is part of the other solution,
. So, ordinarily, you CAN'T have both.\r\n" );
document.write( "4) Solutions to INEQUALITIES are different from solutions to EQUATIONS. Inequalities' solutions need to\r\n" );
document.write( " be determined based on their CRITICAL POINTS' ranges.\r\n" );
document.write( "\r\n" );
document.write( " As such, IGNORE @praseenakos@yahoo.com's \"SOLUTIONS,\" and ACCEPT the SOLUTION-SETS by Tutor @rahman(247)\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The most concise explanation for the solutions?:\r\n" );
document.write( "Solutions.
and x = 1 mean that there're 2 CRITICAL POINTS,
and 1.\r\n" );
document.write( "The solutions will be the RANGES OUTSIDE these 2 critical points, including the critical points.\r\n" );
document.write( "So, for
, the solution set will be the range to the LEFT of
, and
, itself, or:
\r\n" );
document.write( "And, for x = 1, the solution set will be the range to the RIGHT of 1, and 1, or
.
\n" );
document.write( "