document.write( "Question 46425: One day, the temperature at 2:00 A.M. was 43�F, and by 3:00 P.M. the temperature was 56�F. What was the hourly rate of temperature change?\r
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Algebra.Com's Answer #854313 by ikleyn(53804)\"\" \"About 
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\n" ); document.write( "One day, the temperature at 2:00 A.M. was 43°F, and by 3:00 P.M. the temperature was 56°F.
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\n" ); document.write( "\n" ); document.write( "        The solution in the post by  @consc198  is  FATALLY  WRONG,\r
\n" ); document.write( "\n" ); document.write( "        since  @consc198  did not take a labor to read the problem and to think on its meaning.\r
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\n" ); document.write( "\n" ); document.write( "        For a correct solution see what follows.\r
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document.write( "The time interval from 2:00 AM to 3:00 PM is 13 hours.\r\n" );
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document.write( "Therefore, the hourly rate of the temperature change this day is (based on given data)\r\n" );
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document.write( "    \"%2856-43%29%2F13\" = \"13%2F13\" = 1 degree Fahrenheit per hour.\r\n" );
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