document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117405>Question 117405</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0030054192/algebrahomeworkh>Holt Algebra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Find 3 consecutive integers such that 4 times the middle integer plus the largest integer is 9 less than 6 times the smallest. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85427 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85427\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the integers be (n-1), n, (n+1).<BR>\n" );
document.write( "4 times middle integer = 4n<BR>\n" );
document.write( "4 times middle integer plus the larges integer = 4n + (n-1) = 5n-1<BR>\n" );
document.write( "6 times the smallest integer = 6(n-1)\r<BR>\n" );
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document.write( "According to the given conditions<BR>\n" );
document.write( "5n-1 = 6(n-1) - 9<BR>\n" );
document.write( "5n - 1 = 6n - 6 - 9<BR>\n" );
document.write( "5n - 1 = 6n - 15<BR>\n" );
document.write( "6n - 5n = 15 + 1<BR>\n" );
document.write( "n = 16\r<BR>\n" );
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document.write( "Hence, the nos. are (16 - 1 =) 15, 16 and (16 + 1 =) 17. </SPAN>\n" );
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