document.write( "Question 295596: How many ounces of pure alcohol must be added to 40 ounces of a 70% alcohol solution to produce an 85% alcohol solution? \n" ); document.write( "
Algebra.Com's Answer #854264 by ikleyn(53875)\"\" \"About 
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\n" ); document.write( "How many ounces of pure alcohol must be added to 40 ounces of a 70% alcohol solution
\n" ); document.write( "to produce an 85% alcohol solution?
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\n" ); document.write( "\n" ); document.write( "        The solution in the post by @mananth is incorrect.\r
\n" ); document.write( "\n" ); document.write( "        I came to bring a correct solution.\r
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\n" ); document.write( "\n" ); document.write( "let quantity of pure alcohol to be added be x ounces
\n" ); document.write( "70% alcohol is 40 ounces
\n" ); document.write( "the total will be x+40 ounces
\n" ); document.write( "x + 0.7*40 = (x+40)*0.85
\n" ); document.write( "x + 28 = 0.85x + 34
\n" ); document.write( "0.15x = 34 - 28
\n" ); document.write( "0.15x = 6
\n" ); document.write( "x = 6/0.15 = 40.\r
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\n" ); document.write( "\n" ); document.write( "ANSWER.   40  ounces of pure alcohol must be added.\r
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\n" ); document.write( "\n" ); document.write( "CHECK   for the concentration:     \"%2840+%2B+0.7%2A40%29%2F%2840%2B40%29\" = 0.85   !  Precisely correct  !\r
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\n" ); document.write( "\n" ); document.write( "Solved correctly.\r
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\n" ); document.write( "\n" ); document.write( "        Notice that  85%  concentration is precisely midpoint between  70%  and  100%, \r
\n" ); document.write( "\n" ); document.write( "                so the answer is obvious and can be guessed  MENTALLY.\r
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