document.write( "Question 287802: 3/(x+1) +4/(x-2)=(px+q)/(x+1)(x-2)
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Algebra.Com's Answer #854243 by MathTherapy(10839)\"\" \"About 
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document.write( "3/(x+1)   +4/(x-2)=(px+q)/(x+1)(x-2)   \r\n" );
document.write( "What is the value of p and q?\r\n" );
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document.write( "\"3%2F%28x+%2B+1%29+%2B+4%2F%28x+-+2%29+=+%28px+%2B+q%29%2F%28x+%2B+1%29%28x+-+2%29\"   \r\n" );
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document.write( "Let's focus on the LEFT-SIDE of the equation\r\n" );
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document.write( " ---- Multiplying left-side by GCF (x + 1)(x - 2) \r\n" );
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document.write( "                        7x - 2 = px + q --- Equating NUMERATORS, since DENOMINATORS are equivalent\r\n" );
document.write( "                        7x = px          - 2 = q\r\n" );
document.write( "                   \"7x%2Fx+=+px%2Fx\"\r\n" );
document.write( "                  \"7cross%28x%29%2Fcross%28x%29+=+p%2Across%28x%29%2Fcross%28x%29\"____7 = p
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