document.write( "Question 287802: 3/(x+1) +4/(x-2)=(px+q)/(x+1)(x-2)
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Algebra.Com's Answer #854239 by ikleyn(53875)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "        The answer in the post by @mananth is incorrect.\r
\n" ); document.write( "\n" ); document.write( "        I came to bring a correct solution.\r
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\n" ); document.write( "\n" ); document.write( "3/(x+1) +4/(x-2)=(px+q)/(x+1)(x-2)\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by (x+1)*(x-2).
\n" ); document.write( "You will get an equivalent equality\r
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\n" ); document.write( "\n" ); document.write( "3(x-2)+4(x+1)= (px+q)(x+1)(x-2)/(x+1)(x-2)\r
\n" ); document.write( "\n" ); document.write( "3x-6+4x+4 = (px+q)\r
\n" ); document.write( "\n" ); document.write( "7x-2 = px+q\r
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\n" ); document.write( "\n" ); document.write( "Hence, p = 7, q = -2.\r
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\n" ); document.write( "\n" ); document.write( "ANSWER.   p = 7,   q = -2.\r
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\n" ); document.write( "\n" ); document.write( "At this point, the solution is complete.\r
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