document.write( "Question 284285: Hi! I need to ask help for this problem. The answer that I got was $1,200, and I've a nagging feeling that that may be wrong. The problem is:
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document.write( "Mr. A owned 60% of a mill and Mr. B the remainder. Mr. A sold part of what he owned to Mr. B for $1,200, and then Mr. B owned as much as Mr. A. At this rate, how much is the total value of the mill? \n" );
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Algebra.Com's Answer #854224 by greenestamps(13367) You can put this solution on YOUR website! \n" ); document.write( "Certainly the answer of $1200 that you got for the total value must be wrong, since A sold part of his share to B for $1200. But since the correct answer is $12,000, perhaps your work was okay but you got the decimal point in the wrong place. \n" ); document.write( "Initially, A owned 60%; after he sold some to B, the two had equal shares, so A now owned 50%. \n" ); document.write( "That means 10% of the value traded hands, and the amount of that transaction was $1200. Since 10% is one-tenth of the total, the total value is $12,000. \n" ); document.write( "ANSWER: $12,000 \n" ); document.write( " \n" ); document.write( " |