document.write( "Question 1210595: A donut shop sold 3/5 of their glazed donuts in the morning, In the afternoon, they sold 5/6 of the remaining glazed donuts. The ratio of the remaining glazed donuts to the remaining chocolate donuts was 2:7. If they had 42 chocolate donuts left, how many total donuts (glazed + chocolate) did the shop have at the very beginning? \n" ); document.write( "
Algebra.Com's Answer #854221 by ikleyn(53751)\"\" \"About 
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\n" ); document.write( "A donut shop sold 3/5 of their glazed donuts in the morning.
\n" ); document.write( "In the afternoon, they sold 5/6 of the remaining glazed donuts.
\n" ); document.write( "The ratio of the remaining glazed donuts to the remaining chocolate donuts was 2:7.
\n" ); document.write( "If they had 42 chocolate donuts left, how many total donuts (glazed + chocolate) did the shop have
\n" ); document.write( "at the very beginning?
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document.write( "Let 'x' be the number of glazed donuts in the chop at the very beginning.\r\n" );
document.write( "Let 'c' be the number of remaining chocolate donuts, which number is mentioned in the problem:  c = 42.\r\n" );
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document.write( "In the morning the shop sold  \"%283%2F5%29x\"  of their glazed donuts.\r\n" );
document.write( "Hence,  \"%282%2F5%29x\"  glazed donuts remained.\r\n" );
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document.write( "Of this  \"%282%2F5%29x\"  glazed donuts,  \"5%2F6\"  were sold afternoon.\r\n" );
document.write( "So,  \"%282%2F5%29x%2A%285%2F6%29\" = \"%281%2F3%29x\"  glazed donuts were sold afternoon.\r\n" );
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document.write( "Thus  \"%283%2F5%29x\" + \"%281%2F3%29x\" = \"%289%2F15%29x+%2B+%285%2F15%29x\" = \"%2814%2F15%29x\"  glazed donuts \r\n" );
document.write( "were sold during the day, and  \"%281%2F15%29x\"  glazed donut remained at the evening.\r\n" );
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document.write( "From the condition, we can write\r\n" );
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document.write( "    \"%28%281%2F15%29x%29%2Fc\" = \"2%2F7\",  or  \"x%2F%2815c%29\" = \"2%2F7\",\r\n" );
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document.write( "which gives \r\n" );
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document.write( "    x = \"%28%282%2A15%29%2F7%29c\".\r\n" );
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document.write( "Substitute here c= 42 to get  \r\n" );
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document.write( "    x = \"%28%282%2A15%29%2F7%29%2A42\" = 2*15*6 = 180.\r\n" );
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document.write( "So, the starting number of the glazed donuts was 180 at the very beginning.\r\n" );
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document.write( "It is what we can get from the given problem, using all given information.\r\n" );
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document.write( "But we have no any other data to determine the number of the chocolate donuts at the very beginning.\r\n" );
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document.write( "So, in the given form, the problem is DEFECTIVE and does not allow to answer the posed question.\r\n" );
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