document.write( "Question 416707: Please help me solve this equation! log2 x+ log2 (x+1)=1 \n" ); document.write( "
Algebra.Com's Answer #854216 by ikleyn(53750) You can put this solution on YOUR website! . \n" ); document.write( "Please help me solve this equation! log2 x+ log2 (x+1)=1 \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Below is my complete correct solution \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log2(x) + log2(x+1) = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The domain for this equation is the set of all real positive numbers x > 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In this domain, the given equation is equivalent to this one \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log2(x*(x+1)) = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simplify and find x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x(x+1) = 2^1, \n" ); document.write( "x^2+x-2 = 0 \n" ); document.write( "(x+2)(x-1) = 0 \n" ); document.write( "x = -2, 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = -2 is an extraneous solution out the domain, so we disregard x = -2 \n" ); document.write( "(since logarithm of the negative argument is not defined).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thus, x = 1 is the unique real solution to the original equation. <<<---=== ANSWER\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |