document.write( "Question 686407: Please help me solve this equation:\r
\n" ); document.write( "\n" ); document.write( "Solve: log2 (x+5) + log2 (x+1) = 5 \n" ); document.write( "

Algebra.Com's Answer #854214 by MathTherapy(10806) $\"\"$ $\"About$

You can put this solution on YOUR website!

\r\n" );
document.write( "Please help me solve this equation:\r\n" );
document.write( "\r\n" );
document.write( "Solve:  log2 (x+5) + log2 (x+1) = 5\r\n" );
document.write( "***********************************\r\n" );
document.write( "The following response from the other person doesn't do much to answer this problem, or help\r\n" );
document.write( "the \"POSTER: \"log(x+1)/log 2 +log*x+5)/log(2)=5\"\r\n" );
document.write( "\r\n" );
document.write( ", with x > - 1\r\n" );
document.write( "        ------ Applying  = \r\n" );
document.write( "          \r\n" );
document.write( "                       ---- Converting to EXPONENTIAL form\r\n" );
document.write( "                      \r\n" );
document.write( "                    \r\n" );
document.write( "                (x - 3)(x + 9) = 0\r\n" );
document.write( "                               x - 3 = 0     or      x + 9 = 0 ---- Setting each FACTOR equal to 0\r\n" );
document.write( "                                     x = 3    or              x = - 9 (IGNORE)\r\n" );
document.write( "\r\n" );
document.write( "The above x-value, - 9, is IGNORED because x MUST be > - 1, and x = - 9 is CLEARLY NOT!\r\n" );
document.write( "\r\n" );
document.write( "So, only VALID/ACCEPTABLE solution is: x = 3

\n" ); document.write( "

\n" );