document.write( "Question 284297: Fred and Desi left Steamtown Mall at 9:00 am and began walking in opposite directions. At 1:00 pm that same day they were 20 miles apart. If Fred walks 0.5 mph slower than Desi, what is Desi's speed of walking?\r
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document.write( "A. 2.25 mph B. 2.75 mph C. 3.5 mph D. 5 mph E. None of these. \n" );
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Algebra.Com's Answer #854212 by mccravyedwin(421) You can put this solution on YOUR website! \r\n" ); document.write( "Let Desi's speed be R, then Fred's speed is then R-0.5\r\n" ); document.write( "Their speed of separation is the sum of their speeds or R+R-0.5 or 2R-0.5\r\n" ); document.write( "From 9:00 am to 1:00 pm is 4 hours.\r\n" ); document.write( "Distance = Rate x Time\r\n" ); document.write( " 20 = (2R-0.5)T\r\n" ); document.write( " 20 = (2R-0.5)(4) \r\n" ); document.write( " 20 = 8R-2\r\n" ); document.write( " 22 = 8R\r\n" ); document.write( " 22/8 = R\r\n" ); document.write( " 2.75 = R\r\n" ); document.write( "\r\n" ); document.write( "Answer: Desi's speed of walking is 2.75 mph\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |