document.write( "Question 284705: Karen walsh has twice as much money invested at 5% simple interest as she does at 4%. If her yearly income from these two investments is $350, how much does she have invested at each rate. \n" ); document.write( "
Algebra.Com's Answer #854207 by ikleyn(53750) You can put this solution on YOUR website! . \n" ); document.write( "Karen Walsh has twice as much money invested at 5% simple interest as she does at 4%. \n" ); document.write( "If her yearly income from these two investments is $350, how much does she have invested at each rate. \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " In the post by @mananth, the condition is interpreted incorrectly. \n" ); document.write( " As a consequence to it, the setup equation is not adequate to the problem, \n" ); document.write( " as well as the solution and the answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " I came to bring a correct solution.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let the amount invested at 4% be x \n" ); document.write( "The amount invested at 5%i s 2x dollars \n" ); document.write( "The yearly interest obtained is 350 dollars. \n" ); document.write( "0.04x + 0.05*(2x) = 350 \n" ); document.write( "0.04x + 0.1x = 350 \n" ); document.write( "0.14x = 350 \n" ); document.write( "x = 350/0.14 \n" ); document.write( "x = 2500 which is the amount invested at 4% \n" ); document.write( "2*2500 = 5000 dollars is the amount invested at 5%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "CHECK. 0.04*2500 + 0.05*5000 = 350 dollars. ! Precisely correct !\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solved correctly.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |