document.write( "Question 187282This question is from textbook
\n" ); document.write( ": Felipe jobs for 10 miles and then walks another 10 miles. He jobs 2 1/2 miles per hour faster than he walks, and the entire distance of 20 miles takes 6 hours. find the rate at which he walks and the rate at which he jogs. \n" ); document.write( "

Algebra.Com's Answer #854205 by MathTherapy(10806) $\"\"$ $\"About$

You can put this solution on YOUR website!

\r\n" );
document.write( "Felipe jobs for 10 miles and then walks another 10 miles.  He jobs 2 1/2 miles per hour faster than he walks, and\r\n" );
document.write( "the entire distance of 20 miles takes 6 hours.  find the rate at which he walks and the rate at which he jogs.\r\n" );
document.write( "**************************************************************\r\n" );
document.write( "The other person's solution is rather lengthy, and in this author's opinion, a few UNNECESSARY variables were introduced. \r\n" );
document.write( "Furthermore, he suggests using the quadratic formula to solve his final equation, which can be easily FACTORIZED. \r\n" );
document.write( "\r\n" );
document.write( "Let the speed at which he walks, be S\r\n" );
document.write( "Then, his jogging speed = , or S + 2.5\r\n" );
document.write( "Time taken to walk 10 miles: , and time taken to jog 10 miles = \r\n" );
document.write( "As he takes 6 hours to walk and jog 20 miles, we get the following\r\n" );
document.write( "TOTAL-TIME equation: \r\n" );
document.write( "                              10(S + 2.5) + 10S = 6S(S + 2.5) ----- Multiplying by LCD, S(S + 2.5)\r\n" );
document.write( "                                     \r\n" );
document.write( "                                              \r\n" );
document.write( "                           \r\n" );
document.write( "                                      \r\n" );
document.write( "                          \r\n" );
document.write( "                        \r\n" );
document.write( "                               (2S - 5)(3S + 5) = 0\r\n" );
document.write( "                                                 2S - 5 = 0      or     3S + 5 = 0 ---- Setting FACTORS equal to 0\r\n" );
document.write( "                                                      2S = 5      or            3S = - 5 (IGNORE)\r\n" );
document.write( "                  Walking speed, or S =  = 2.5 mph\r\n" );
document.write( "\r\n" );
document.write( "                 Jogging speed: S + 2.5 = 2.5 + 2.5 = 5 mph\r\n" );
document.write( "\r\n" );
document.write( "                 You can do the CHECK!!

\n" ); document.write( "

\n" );