document.write( "Question 1195448: Clifford had 80% fewer sweets than Ashwin. After Ashwin gave 210 sweets to Clifford, Clifford had 2/3 as many sweets as Ashwin. How many sweets did each of them have in the end?
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Algebra.Com's Answer #854196 by MathTherapy(10801)\"\" \"About 
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document.write( "Clifford had 80% fewer sweets than Ashwin. After Ashwin gave 210 sweets to Clifford, Clifford had 2/3 as many sweets as Ashwin. How many sweets did each of them have in the end?\r\n" );
document.write( "(a) Ashwin\r\n" );
document.write( "(b) Clifford\r\n" );
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document.write( "Let amount Ashwin started with, be A\r\n" );
document.write( "Since \"Clifford had 80% fewer sweets than Ashwin,\" then Clifford started with (1 - 80%) of A, or .2A\r\n" );
document.write( "When Ashwin gave 210 sweets to Clifford, Ashwin had A - 210 left\r\n" );
document.write( "After receiving 210 from Ashwin, Clifford ended up with .2A + 210\r\n" );
document.write( "With Clifford ending up with \"2%2F3\" as many sweets as Ashwin, we get the following FINAL-COUNT equation:\r\n" );
document.write( "                                                     \"%282%2F3%29%28A+-+210%29+=+.2A+%2B+210\"\r\n" );
document.write( "                                                          2(A - 210) = .6A + 630 -- Multiplying by LCD, 3\r\n" );
document.write( "                                                             2A - 420 = .6A + 630\r\n" );
document.write( "                                                              2A - .6A = 630 + 420\r\n" );
document.write( "                                                                    1.4A = 1,050\r\n" );
document.write( "Number of sweets Ashwin started with, or \"A+=+%221%2C050%22%2F1.4+=+%2210%2C500%22714+=+highlight%28+750%29\"\r\n" );
document.write( "Number of sweets Clifford started with: .2A = .2(750) = 150
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