document.write( "Question 283256: A mother is twice as old as her daughter now, but 10 years ago, she was 3 times as
\n" ); document.write( "old as her daughter. Find their ages at present.
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Algebra.Com's Answer #854194 by ikleyn(53742)\"\" \"About 
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\n" ); document.write( "A mother is twice as old as her daughter now, but 10 years ago, she was 3 times as
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\n" ); document.write( "\n" ); document.write( "        In the post by @mananth, the setup equation is written incorrectly.\r
\n" ); document.write( "\n" ); document.write( "        His manipulations that follow this incorrect equation, also have many errors,\r
\n" ); document.write( "\n" ); document.write( "        although the final answer is correct.\r
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\n" ); document.write( "\n" ); document.write( "        His solution can not be considered as an etalon, so I came to bring a correct solution.\r
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\n" ); document.write( "\n" ); document.write( "Let the daughter's age be x
\n" ); document.write( "mother's age will be 2x
\n" ); document.write( "Ten years ago
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\n" ); document.write( "\n" ); document.write( "3(x-10) = 2x-10         <<<---=== This is a  CORRECT  setup equation\r
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\n" ); document.write( "\n" ); document.write( "Simplify and find 'x'\r
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\n" ); document.write( "\n" ); document.write( "3x-30 = 2x-10
\n" ); document.write( "3x-2x = 30-10
\n" ); document.write( "x = 20 Daughter's age now
\n" ); document.write( "Mother's age is 2x = 2*20 = 40 years\r
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\n" ); document.write( "\n" ); document.write( "Solved correctly.\r
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