document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=282321>Question 282321</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A jogger started a course at 4.5 mph.  A cyclist started the same course 1 hour later at an average speed of 14 mph.  How long after the jogger started did the cyclist take over the jogger?  Round to the nearest tenth of an hour. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #854191 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13326)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=854191\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "When the cyclist starts, the jogger has been running for an hour at 4.5 mph, covering a distance of 4.5 miles.<br><BR>\n" );
document.write( "The rate at which the cyclist catches up to the jogger is the difference in their rates, which is 14-4.5 = 9.5 mph.<br><BR>\n" );
document.write( "The time required for the cyclist to catch up to the jogger is the catch-up distance divided by catch-up the rate, which is 4.5/9.5 = 9/19 hours.<br><BR>\n" );
document.write( "The question asks for the time after the jogger starts for the cyclist to catch up to the jogger; that is 1 + 9/19 = 28/19 hours.<br><BR>\n" );
document.write( "28/19 = 1.4736...<br><BR>\n" );
document.write( "Rounded to the nearest tenth of an hour, per the instructions...<br><BR>\n" );
document.write( "ANSWER: 1.5 hours<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );