document.write( "Question 282321: A jogger started a course at 4.5 mph. A cyclist started the same course 1 hour later at an average speed of 14 mph. How long after the jogger started did the cyclist take over the jogger? Round to the nearest tenth of an hour. \n" ); document.write( "
Algebra.Com's Answer #854186 by josgarithmetic(39790)\"\" \"About 
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document.write( "                 SPEED        TIME         DISTANCE\r\n" );
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document.write( "JOGGER          4.5            t            4.5t\r\n" );
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document.write( "CYCLIST         14           t-1          14(t-1)\r\n" );
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\n" ); document.write( "\"4.5t=14t-14\"\r
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\n" ); document.write( "\n" ); document.write( "\"14t-4.5t=14\"\r
\n" ); document.write( "\n" ); document.write( "\"9.5t=14\"\r
\n" ); document.write( "\n" ); document.write( "\"t=14%2F9.5\"\r
\n" ); document.write( "\n" ); document.write( "\"t=1.4737\"
\n" ); document.write( "1 hour 28 minutes\r
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\n" ); document.write( "\n" ); document.write( "The cyclist needed 28 minutes (and a few more seconds) to catchup.
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