document.write( "Question 282321: A jogger started a course at 4.5 mph. A cyclist started the same course 1 hour later at an average speed of 14 mph. How long after the jogger started did the cyclist take over the jogger? Round to the nearest tenth of an hour. \n" ); document.write( "

Algebra.Com's Answer #854182 by ikleyn(53742) $\"\"$ $\"About$

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\n" ); document.write( "A jogger started a course at 4.5 mph. A cyclist started the same course 1 hour later at an average speed of 14 mph.
\n" ); document.write( "How long after the jogger started did the cyclist take over the jogger? Round to the nearest tenth of an hour.
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\n" ); document.write( "\n" ); document.write( " Calculations and the answer in the post by @mananth are not accurate\r
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document.write( "When the cyclist starts, the jogger is 4.5 miles ahead.\r\n" );
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document.write( "The rate of approaching is  14 - 4.5 = 9.5 miles per hour.\r\n" );
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document.write( "Therefore, the time when the cyclist will take over the jogger is  \r\n" );
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document.write( "     =  =  = 0.474 of an hour, or 28.42 minutes after the cyclist' start.\r\n" );
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document.write( "The distance from the start to the catching point is  , which is about 6.632 mile.\r\n" );
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document.write( "ANSWER.  The time when the cyclist will take over the jogger is 0.474 of an hour, or 28.42 minutes.\r\n" );
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document.write( "         The distance from the start to the catching point is  about 6.632 mile.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved correctly.\r
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