document.write( "Question 282711: Four gallons of a 45% acid solution is obtained by mixing a 90% solution with a 30% solution. How many gallons of each solution must be used to obtain the desired mixture? \n" ); document.write( "
Algebra.Com's Answer #854178 by josgarithmetic(39790)\"\" \"About 
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v gallons of 90%
\n" ); document.write( "4-v gallons of 30%
\n" ); document.write( "result concentration 45%\r
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\n" ); document.write( "\n" ); document.write( "\"90v%2B30%284-v%29=45%2A4\"\r
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\n" ); document.write( "\n" ); document.write( "\"90v-30v%2B30%2A4=45%2A4\"\r
\n" ); document.write( "\n" ); document.write( "\"%2890-30%29v%2B30%2A4=45%2A4\"\r
\n" ); document.write( "\n" ); document.write( "\"%2890-30%29v=45%2A4-30%2A4\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28v=4%28%2845-30%29%2F%2890-30%29%29%29\"
\n" ); document.write( "Compute this and evaluate \"4-v\".
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