document.write( "Question 279596: Pablo can drive 5 times as fast as Oscar can ride his bicycle. If it takes Oscar 4 hours longer than Pablo to travel 90 miles, how fast can Oscar ride his bicycle? \n" ); document.write( "
Algebra.Com's Answer #854176 by MathTherapy(10801)\"\" \"About 
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document.write( "Pablo can drive 5 times as fast as Oscar can ride his bicycle. If it takes Oscar 4 hours longer than\r\n" );
document.write( "Pablo to travel 90 miles, how fast can Oscar ride his bicycle?\r\n" );
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document.write( "Let Oscar's riding-speed be S\r\n" );
document.write( "Since Pablo's driving-speed is 5 times as fast as Oscar's riding-speed, then Pablo's driving-speed is 5S\r\n" );
document.write( "With distance being 90 miles, Oscar's time to cover this distance = \"90%2FS\", while Pablo's is \"90%2F%285S%29+=+18%2FS\" \r\n" );
document.write( "It's stated that \"it takes Oscar 4 hours longer than Pablo to travel 90 miles....\". This gives us the\r\n" );
document.write( "following TIME equation: \"90%2FS+-+18%2FS+=+4\"\r\n" );
document.write( "                                          \"%2890+-+18%29%2FS+=+4\" \r\n" );
document.write( "                                                    \"72%2FS+=+4\" \r\n" );
document.write( "                                                    4S = 72 -- Cross-multiplying\r\n" );
document.write( "            Oscar's riding-speed, or \"S+=+72%2F4+=+highlight%28matrix%281%2C2%2C+18%2C+mph%29%29\"
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