document.write( "Question 279490: The sum of the digits of a two- digit number is 12. If 36 is added to the number, then the number obtained is the original with its digits interchanged. Find the original number. \n" ); document.write( "
Algebra.Com's Answer #854163 by ikleyn(53742)\"\" \"About 
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\n" ); document.write( "The sum of the digits of a two- digit number is 12. If 36 is added to the number, then the number obtained
\n" ); document.write( "is the original with its digits interchanged. Find the original number.
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\n" ); document.write( "\n" ); document.write( "        The solution in the post by @mananth, giving the answer '43 ' is incorrect,\r
\n" ); document.write( "\n" ); document.write( "        as anybody can check by substituting it to the problem.\r
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\n" ); document.write( "\n" ); document.write( "        I came to bring a correct and accurate solution.\r
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\n" ); document.write( "\n" ); document.write( "Let x be in the tens place and y in units place
\n" ); document.write( "x+y =12
\n" ); document.write( "10x+y+36 = 10y+x
\n" ); document.write( "10x-10y+y-x+36=0
\n" ); document.write( "9x-9y=-36
\n" ); document.write( "x+y=12
\n" ); document.write( "9x+9y=108
\n" ); document.write( "18x=72
\n" ); document.write( "x=4
\n" ); document.write( "x+y=12 but x=4 so y=8. \r
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\n" ); document.write( "\n" ); document.write( "The number is 48.         ANSWER\r
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\n" ); document.write( "\n" ); document.write( "Solved correctly.\r
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