document.write( "Question 734457: log10x-log(x-3)=log2 \n" ); document.write( "

Algebra.Com's Answer #854158 by MathTherapy(10801) $\"\"$ $\"About$

You can put this solution on YOUR website!

\r\n" );
document.write( "log10x-log(x-3)=log2\r\n" );
document.write( "********************\r\n" );
document.write( " is NOT a solution to this logarithmic equation, as stated by the other person, since it's EXTRANEOUS!\r\n" );
document.write( "\r\n" );
document.write( "log (10x) - log (x - 3) = log (2)\r\n" );
document.write( "x - 3 is the smaller of the 2 variable-arguments, and so, MUST be > 0. This gives us: x - 3 > 0 ====> x > 3\r\n" );
document.write( "We then have: log (10x) - log (x - 3) = log (2), with x > 3\r\n" );
document.write( "While the solution to this equation is x = , this value is NOT > 3, and so, is INVALID/UNACCEPTABLE. \r\n" );
document.write( "\r\n" );
document.write( "As a result, NO SOLUTION exists for this equation!.

\n" ); document.write( "

\n" );