document.write( "Question 883161: log2(x - 6) + log2(x - 4) = log2 x solve the logarithmic equation. and round. \n" ); document.write( "

Algebra.Com's Answer #854157 by MathTherapy(10801) $\"\"$ $\"About$

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document.write( "log2(x - 6) + log2(x - 4) = log2 x solve the logarithmic equation. and round. \r\n" );
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document.write( "x = 3 or x = 8, as stated by the other person, is partly WRONG!   \r\n" );
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document.write( "Looking at the logarithmic equation, the smallest log argument, x - 6 MUST be > 0.\r\n" );
document.write( "So, x - 6 > 0, and therefore, x > 6. \r\n" );
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document.write( "We then have: , with x > 6\r\n" );
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document.write( "The x-value 3 is NOT > 6, which makes it EXTRANEOUS and an INVALID/UNACCEPTABLE solution. On the\r\n" );
document.write( "other hand, the x-value 8 is > 6, which makes it the ONLY solution to this equation.

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