document.write( "Question 1124074: The sum of three numbers is 10. The sum of twice the first​ number, 5 times the second​ number, and 6 times the third number is 53. The difference between 7 times the first number and the second number is 4. \r
\n" ); document.write( "\n" ); document.write( "Find the three numbers.
\n" ); document.write( "first​ number:\r
\n" ); document.write( "\n" ); document.write( "second​ number: \r
\n" ); document.write( "\n" ); document.write( "third​ number:
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Algebra.Com's Answer #854137 by josgarithmetic(39780)\"\" \"About 
You can put this solution on YOUR website!
\"system%28x%2By%2Bz=10%2C2x%2B5y%2B6z=53%2C7x-y=4%29\"\r
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\n" ); document.write( "\n" ); document.write( "What if first try to eliminate z?
\n" ); document.write( "\"system%286x%2B6y%2B6z=60%2C2x%2B5y%2B6z=53%29\"\r
\n" ); document.write( "\n" ); document.write( "Subtract later from former.
\n" ); document.write( "\"4x%2By=7\"\r
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\n" ); document.write( "\n" ); document.write( "Revising the system now having just two variables,
\n" ); document.write( "\"syste%284x%2By=7%2C7x-y=4%29\"\r
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\n" ); document.write( "\n" ); document.write( "Add the parts.
\n" ); document.write( "\"11x%2B0=11\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Using E3 of original system
\n" ); document.write( "\"7x-4=y\"
\n" ); document.write( "\"7-4=y\"
\n" ); document.write( "\"highlight%28y=3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Using E1 of original system
\n" ); document.write( "\"1%2B3%2Bz=10\"
\n" ); document.write( "\"highlight%28z=6%29\"
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