document.write( "Question 1124074: The sum of three numbers is 10. The sum of twice the first number, 5 times the second number, and 6 times the third number is 53. The difference between 7 times the first number and the second number is 4. \r
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document.write( "Find the three numbers.
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document.write( "first number:\r
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document.write( "second number: \r
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document.write( "third number: \n" );
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Algebra.Com's Answer #854137 by josgarithmetic(39780) ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "What if first try to eliminate z? \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract later from former. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Revising the system now having just two variables, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add the parts. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using E3 of original system \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using E1 of original system \n" ); document.write( " \n" ); document.write( " |