document.write( "Question 275471: The first of two numbers is one more than twice the second. The sum of twice the first number and three times the second number is 51. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #854128 by josgarithmetic(39792)\"\" \"About 
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The numbers
\n" ); document.write( "\"1%2B2n\", and \"n\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%281%2B2n%29%2B3n=51\"\r
\n" ); document.write( "\n" ); document.write( "\"2%2B4n%2B3n=51\"\r
\n" ); document.write( "\n" ); document.write( "\"7n=51-2\"\r
\n" ); document.write( "\n" ); document.write( "\"7n=49\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28n=7%29\"\r
\n" ); document.write( "\n" ); document.write( "First number is \"highlight%2815%29\".
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