document.write( "Question 275504: if you take a certain two-digit number and reverse its digits to get another two-digit number, then add these two numbers together, their sum is 132. what is the original number? \n" ); document.write( "
Algebra.Com's Answer #854111 by greenestamps(13327) You can put this solution on YOUR website! \n" ); document.write( "While a formal algebraic solution was probably wanted, note that you can also work this problem using logical reasoning and the basic process of adding two 2-digit numbers. In \"coded\" form, you have this addition, where A and B are the two digits of the original number and S is the sum of those two digits (S is not a digit, because the sum of the two 2-digit numbers is 3 digits): \r\n" ); document.write( " A B\r\n" ); document.write( " + B A\r\n" ); document.write( " ------\r\n" ); document.write( " S S \n" ); document.write( "Now that sum has the sum \"S\" in the 10s column and also in the units column, so the value of that sum is 10S + 1S = 11S. \n" ); document.write( "But the sum is 132, so 11S = 132, so S = 132/11 = 12. \n" ); document.write( "So we know that the sum of the two digits A and B is 12. \n" ); document.write( "However, we have no other information to use to find a unique solution to the problem. So the original number can be any 2-digit number in which the sum of the two digits is 12: 39, 48, 57, 66, 75, 84, or 93. Notice that the statement of the problem did not require the two digits of the original number to be different, so 66 is one of the possible answers. \n" ); document.write( "ANSWERS: any of the numbers 39, 48, 57, 66, 75, 84, or 93 \n" ); document.write( " \n" ); document.write( " |