document.write( "Question 117415: Pls help!!! : A coil of wire has a mass of 1.2 kg. The diameter of the wire is 2mm. 1cm^3 of the wire weighs 6.8g. Find the length of the wire and correct to the nearest metre. \n" ); document.write( "
Algebra.Com's Answer #85411 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The diameter of the wire is 2 mm
\n" ); document.write( "1 mm = .001 m
\n" ); document.write( "2 mm = .002 m
\n" ); document.write( "The cross-section area of the wire is
\n" ); document.write( "\"A+=+pi%2Ar%5E2\"
\n" ); document.write( "\"A+=+pi%2A.001%5E2\"
\n" ); document.write( "\"A+=+3.1416%2A10%5E-6\"
\n" ); document.write( "The volume of the wire is
\n" ); document.write( "\"A%2AL\" where L is the length
\n" ); document.write( "Since a known volume has a known weight,
\n" ); document.write( "I can set up a proportion
\n" ); document.write( "6.8 g / 1 cm3 = 1200 g / V
\n" ); document.write( "1 cm3 = .0001 m3
\n" ); document.write( "\"6.8+%2F+10%5E-4+=+1.2%2A10%5E3+%2F+V\"
\n" ); document.write( "multiply both sides by V
\n" ); document.write( "\"6.8V+%2F+10%5E-4+=+1.2%2A10%5E3\"
\n" ); document.write( "multiply both sides by 10^-4
\n" ); document.write( "\"6.8V+=+1.2%2A10%5E3%2A10%5E-4\"
\n" ); document.write( "divide both sides by 6.8
\n" ); document.write( "\"V+=+1.2%2A10%5E-1+%2F+6.8\"
\n" ); document.write( "\"V+=+.017647\"
\n" ); document.write( "\"V+=+A%2AL\"
\n" ); document.write( "\"L+=+V+%2F+A\"
\n" ); document.write( "\"L+=+1.7647%2A10%5E-2+%2F+%283.1416%2A10%5E-6%29\"
\n" ); document.write( "\"L+=+%281.7647+%2F+3.1416%29%2A10%5E4\"
\n" ); document.write( "\"L+=+.5617%2A10%5E4\"
\n" ); document.write( "\"L+=+5.617%2A10%5E3\"m
\n" ); document.write( "The length to the nearest meter is 5,617 m
\n" ); document.write( "check answer
\n" ); document.write( "\"6.8+%2F+10%5E-4+=+1.2%2A10%5E3+%2F+V\"
\n" ); document.write( "\"6.8+%2F+10%5E-4+=+1.2%2A10%5E3+%2F+%28A%2AL%29\"
\n" ); document.write( "\"6.8+%2F+10%5E-4+=+1.2%2A10%5E3+%2F+%283.14159%2A10%5E-6%2A5.617%2A10%5E3%29\"
\n" ); document.write( "\"6.8%2A10%5E4+=+1.2%2A10%5E6+%2F+%283.14159%2A5.617%29\"
\n" ); document.write( "\"6.8%2A10%5E4+=+1.2%2A10%5E6+%2F+1.7646%2A10%5E1\"
\n" ); document.write( "\"6.8%2A10%5E4+=+.68004%2A10%5E5\"
\n" ); document.write( "\"6.8+=+6.8004\"
\n" ); document.write( "close enough
\n" ); document.write( "
\n" );