document.write( "Question 275504: if you take a certain two-digit number and reverse its digits to get another two-digit number, then add these two numbers together, their sum is 132. what is the original number? \n" ); document.write( "

Algebra.Com's Answer #854109 by josgarithmetic(39792) $\"\"$ $\"About$

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The number, 10t+u
\n" ); document.write( "Reversed number t+10u\r
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\n" ); document.write( "\n" ); document.write( "Their sum is 132.
\n" ); document.write( " $\"%2810t%2Bu%29%2B%28t%2B10u%29=132\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"11t%2B11u=132\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"t%2Bu=132%2F11\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"t%2Bu=12\"$ \r
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\n" ); document.write( "\n" ); document.write( "You have some possibilities. each digit is between 1 and 9 inclusive.\r
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document.write( "DIGITS         132 SUM\r\n" );
document.write( "1                   NO.\r\n" );
document.write( "2                   NO.\r\n" );
document.write( "3     9       39+93=yes\r\n" );
document.write( "4     8       48+84=yes\r\n" );
document.write( "5     7       57+75=yes\r\n" );
document.write( "6     6       66+66=yes\r\n" );
document.write( "7     5             yes\r\n" );
document.write( "8     4             yes\r\n" );
document.write( "9     3             yes\r\n" );
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