document.write( "Question 269702: The time it takes to do homework includes a fixed amount of time to prepare plus a constant amount of time per problem. If a student can do 5 homework problems in 40 minutes, and 10 problems in 70 minutes, how many minutes will 25 problems take? \n" ); document.write( "
Algebra.Com's Answer #854076 by ikleyn(53742) You can put this solution on YOUR website! . \n" ); document.write( "The time it takes to do homework includes a fixed amount of time to prepare plus a constant amount of time per problem. \n" ); document.write( "If a student can do 5 homework problems in 40 minutes, and 10 problems in 70 minutes, how many minutes will 25 problems \n" ); document.write( "take? \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Calculations in the post by @mananth are incorrect.\r \n" ); document.write( "\n" ); document.write( " I came to bring a correct solution.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let the fixed time taken be x \n" ); document.write( "The time to solve a problem be y \n" ); document.write( "x+5y=40------------1 \n" ); document.write( "x+10y=70-----------2 \n" ); document.write( "subtract equation 2 from 1 \n" ); document.write( "(x+5y) - (x+10y) = 40-70 \n" ); document.write( "x+5y -x-10y = -30 \n" ); document.write( "-5y = -30 \n" ); document.write( "y = -30/-5 \n" ); document.write( "y = 6. Time taken to solve each problem is 6 minutes \n" ); document.write( "x + 5y = 40 substitute the value of y in the equation \n" ); document.write( "x + 30 = 40 \n" ); document.write( "x = 40-30 = 10 minutes will be the fixed time \n" ); document.write( "25 problems will take (10 minutes + 6 *25) \n" ); document.write( "= 160 minutes or 2 hours and 40 minutes. ANSWER\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |