document.write( "Question 268365: i need help finding x in the equation: 2(squareroot x) + 3 = x \n" ); document.write( "
Algebra.Com's Answer #854072 by josgarithmetic(39790)\"\" \"About 
You can put this solution on YOUR website!
\"2%2Asqrt%28x%29%2B3=x\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Asqrt%28x%29=x-3\"\r
\n" ); document.write( "\n" ); document.write( "\"4x=x%5E2-6x%2B9\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-10x%2B9=0\"\r
\n" ); document.write( "\n" ); document.write( "discriminant \"100-4%2A9=100-36=64\"\r
\n" ); document.write( "\n" ); document.write( "\"x=10%2B-+sqrt%2864%29%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%2810%2B-+8%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"x=5%2B-+4\"\r
\n" ); document.write( "\n" ); document.write( "\"x=1\" \"or\" \"x=9\" -------------check if either or both work
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