document.write( "Question 759176: Find the exact value solution \r
\n" ); document.write( "\n" ); document.write( "log (5x) + log (x-1) = 2 \n" ); document.write( "
Algebra.Com's Answer #854060 by MathTherapy(10806)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "Find the exact value solution \r\n" );
document.write( "\r\n" );
document.write( "log (5x) + log (x-1) = 2\r\n" );
document.write( "*************************************\r\n" );
document.write( "x = 5 or  -  4, as stated by the other person, is partly WRONG!   \r\n" );
document.write( "\r\n" );
document.write( "log (5x) + log (x - 1) = 2\r\n" );
document.write( "Looking at the logarithmic equation, the smaller log argument, x  -  1 MUST be > 0.\r\n" );
document.write( "So, x  -  1 > 0, and therefore, x > 1. \r\n" );
document.write( "\r\n" );
document.write( "We then have: log (5x) + log (x - 1) = 2, with x > 1\r\n" );
document.write( "\r\n" );
document.write( "So, x = 5 is the ONLY solution, as x = - 4 is EXTRANEOUS.
\n" ); document.write( "
\n" );