document.write( "Question 60848: help on this please,,thanks
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document.write( "x+1= sqrt x+7 \n" );
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Algebra.Com's Answer #854049 by ikleyn(53742) You can put this solution on YOUR website! . \n" ); document.write( "help on this please,, thanks \n" ); document.write( "x+1= sqrt(x+7) \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " The solution in the post by @jai_kos is incorrect.\r \n" ); document.write( "\n" ); document.write( " See my correct solution below.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+1= sqrt(x+7)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Square on both sides, we get\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x+1)^2 = x +7 \n" ); document.write( "x^2 + 2x + 1 = x + 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Reduce it to the standard form quadratic equation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 + x - 6 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Factor left side\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x+3)*(x-2) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The roots of this equation are x = -3 and x = 2. \n" ); document.write( "Direct check shows that x = 2 is the solution to the original equation, while x = -3 is an EXTRANEOUS solution.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ANSWER. The given equation has a unique solution in real numbers x = 2.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solved correctly.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |