document.write( "Question 60848: help on this please,,thanks
\n" ); document.write( "x+1= sqrt x+7
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Algebra.Com's Answer #854049 by ikleyn(53742)\"\" \"About 
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\n" ); document.write( "help on this please,, thanks
\n" ); document.write( "x+1= sqrt(x+7)
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\n" ); document.write( "\n" ); document.write( "        The solution in the post by @jai_kos is incorrect.\r
\n" ); document.write( "\n" ); document.write( "        See my correct solution below.\r
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\n" ); document.write( "\n" ); document.write( "x+1= sqrt(x+7)\r
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\n" ); document.write( "\n" ); document.write( "Square on both sides, we get\r
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\n" ); document.write( "\n" ); document.write( "(x+1)^2 = x +7
\n" ); document.write( "x^2 + 2x + 1 = x + 7\r
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\n" ); document.write( "\n" ); document.write( "Reduce it to the standard form quadratic equation\r
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\n" ); document.write( "\n" ); document.write( "x^2 + x - 6 = 0\r
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\n" ); document.write( "\n" ); document.write( "Factor left side\r
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\n" ); document.write( "\n" ); document.write( "(x+3)*(x-2) = 0\r
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\n" ); document.write( "\n" ); document.write( "The roots of this equation are x = -3 and x = 2.
\n" ); document.write( "Direct check shows that x = 2 is the solution to the original equation, while x = -3 is an EXTRANEOUS solution.\r
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\n" ); document.write( "\n" ); document.write( "ANSWER. The given equation has a unique solution in real numbers x = 2.\r
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\n" ); document.write( "\n" ); document.write( "Solved correctly.\r
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