document.write( "Question 1210583: Solve 3^2x-1=27 \n" ); document.write( "
Algebra.Com's Answer #854040 by math_tutor2020(3835)\"\" \"About 
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\n" ); document.write( "If the equation is \"3%5E%282x-1%29+=+27\" then we can rewrite 27 as \"3%5E3\" to arrive at \"3%5E%282x-1%29+=+3%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "Each base is the same (3), so the exponents must be equal in order for the original equation to be valid.\r
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\n" ); document.write( "\n" ); document.write( "Once you arrive at \"2x-1+=+3\" it should be fairly easy to solve. I'll let the student take over from here.
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