document.write( "Question 63264: solve. x-2/x+1 greater or equal to 3
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Algebra.Com's Answer #854039 by ikleyn(53750)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "        The solution in the post by @jai_kos in incorrect.\r
\n" ); document.write( "\n" ); document.write( "        It is incorrect methodologically and gives incorrect answer.\r
\n" ); document.write( "\n" ); document.write( "        See my correct solution below.\r
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document.write( "They want you solve this inequality\r\n" );
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document.write( "    \"%28x-2%29%2F%28x%2B1%29\" >= 3.    (1)\r\n" );
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document.write( "Transform it equivalently this way\r\n" );
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document.write( "    \"%28x-2%29%2F%28x%2B1%29\" - 3 >= 0             <<<---===  moving 3 from right side to left side with changing the sign\r\n" );
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document.write( "    \"%28x-2%29%2F%28x%2B1%29\" - \"%283%28x%2B1%29%29%2F%28x%2B1%29\" >= 0    <<<---=== writing '3' with the common denominator\r\n" );
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document.write( "    \"%28%28x-2%29+-+3%28x%2B1%29%29%2F%28x%2B1%29\" >= 0       <<<---===  simplifying\r\n" );
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document.write( "    \"%28-2x+-5%29%2F%28x%2B1%29\" >= 0               <<<---===  simplifying further\r\n" );
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document.write( "Now, the left side rational function can be non-negative if and only if\r\n" );
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document.write( "    EITHER the numerator is non-negative and denominator is positive\r\n" );
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document.write( "        -2x - 5 >= 0  and  x + 1 > 0    (2)\r\n" );
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document.write( "    OR     the numerator is non-positive and denominator is negative\r\n" );
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document.write( "        -2x - 5 <= 0  and  x + 1 < 0.   (3)\r\n" );
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document.write( "In case (2),  -2x >= 5  and  x > -1,  which is the same as  \r\n" );
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document.write( "              x <= -5/2 and  x > -1.\r\n" );
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document.write( "              These both inequalities, taken together, has no solution.\r\n" );
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document.write( "In case (3),  -2x <= 5  and  x < -1,  which is the same as  \r\n" );
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document.write( "              x >= -5/2 and  x < -1.\r\n" );
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document.write( "Thus the final solution to the given inequality is this set of real numbers  -5/2 <= x < -1,\r\n" );
document.write( "or, in the interval notation, the set [\"-5%2F2%29\",\"-1\").\r\n" );
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\n" ); document.write( "\n" ); document.write( "The error made by  @jai_kos is that when he multiplies both sides of the original inequality by  (x+1),
\n" ); document.write( "he misses the case when  (x+1)  is negative,  which requires different treatment.\r
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\n" ); document.write( "\n" ); document.write( "This error,  which jai_kos makes solving the problem,  is a typical error,  which beginners make
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\n" ); document.write( "until the more experienced teachers/tutors will explain their error and will show a right way solving.\r
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