document.write( "Question 265347: The square of the first of three consecutive odd integers is 9 more than 6 times the sum of the second and the first. Find the numbers.
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Algebra.Com's Answer #854020 by timofer(155) $\"\"$ $\"About$

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These consecutive odd integers may be x, x+2, x+4.\r
\n" ); document.write( "\n" ); document.write( "Guessing that the \"sum of the second and third\" was really meant, then
\n" ); document.write( " $\"x%5E2=6%28x%2B2%2Bx%2B4%29%2B9\"$
\n" ); document.write( " $\"x%5E2=6%282x%2B6%29%2B9\"$
\n" ); document.write( " $\"x%5E2=12x%2B36%2B9\"$
\n" ); document.write( " $\"x%5E2=12x%2B45\"$
\n" ); document.write( " $\"x%5E2-12x=45\"$
\n" ); document.write( " $\"x%28x-12%29=45\"$
\n" ); document.write( " $\"x%28x-12%29=15%2A3=45\"$
\n" ); document.write( "This means the first integer would be 15.\r
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\n" ); document.write( "\n" ); document.write( "The way the given problem was described cannot be correct. \n" ); document.write( "

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