document.write( "Question 117403: Carla invested $28,000, part at 14% and part 9%. IF the total interest at the end of the year is $3,370, how much did she invest at 14%? \n" ); document.write( "
Algebra.Com's Answer #85402 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Let x be invested at 14% and 28000-x be invested at 9%. \n" ); document.write( ".14x+.09(28000-x)=3370 \n" ); document.write( ".14x+2520-.09x=3370 \n" ); document.write( ".05x+2520-2520=3370-2520 \n" ); document.write( ".05x=850 \n" ); document.write( ".05x/.05=850/.05 \n" ); document.write( "x=$17,000 \n" ); document.write( ". \n" ); document.write( "Check \n" ); document.write( "17000*.14+11000*.09=3370 \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |