document.write( "Question 117403: Carla invested $28,000, part at 14% and part 9%. IF the total interest at the end of the year is $3,370, how much did she invest at 14%? \n" ); document.write( "
Algebra.Com's Answer #85402 by edjones(8007)\"\" \"About 
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Let x be invested at 14% and 28000-x be invested at 9%.
\n" ); document.write( ".14x+.09(28000-x)=3370
\n" ); document.write( ".14x+2520-.09x=3370
\n" ); document.write( ".05x+2520-2520=3370-2520
\n" ); document.write( ".05x=850
\n" ); document.write( ".05x/.05=850/.05
\n" ); document.write( "x=$17,000
\n" ); document.write( ".
\n" ); document.write( "Check
\n" ); document.write( "17000*.14+11000*.09=3370
\n" ); document.write( ".
\n" ); document.write( "Ed
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