document.write( "Question 262142: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train B is traveling at 60 miles per hour. Train A passes a station at 5:25 A.M. If train B passes the same station at 5:37 A.M, at what time will train B catch up to train A? \n" ); document.write( "

Algebra.Com's Answer #853972 by ikleyn(53742) $\"\"$ $\"About$

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\n" ); document.write( "Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour
\n" ); document.write( "and train B is traveling at 60 miles per hour. Train A passes a station at 5:25 A.M. If train B passes the same
\n" ); document.write( "station at 5:37 A.M, at what time will train B catch up to train A?
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\n" ); document.write( "\n" ); document.write( " The solution in the post by @mananth is incorrect due to his errors in reasoning and in calculations.\r
\n" ); document.write( "\n" ); document.write( " I came to bring a correct solution.\r
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document.write( "At 5:37 AM,  train A is  40 mph x 12 minutes = 40 mph x 0.2 of an hour = 8 miles ahead train B,\r\n" );
document.write( "and the rate of approaching train B to train A is  60-40 = 20 mph.\r\n" );
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document.write( "So, train B will catch train A in   =  = 24 minutes.\r\n" );
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document.write( "So, the catching time is 5:37 AM plus 24 minutes, which is  6:01 AM.\r\n" );
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document.write( "ANSWER.  The catching time is  6:01 AM.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved correctly.\r
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