document.write( "Question 1000209: A man invests his savings in two accounts, one paying 6 percent and the other paying 10 percent simple interest per year.
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document.write( "He puts twice as much in the lower-yielding account because it is less risky. His annual interest is 3960 dollars.
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document.write( "How much did he invest at each rate? \n" );
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Algebra.Com's Answer #853967 by ikleyn(53742) You can put this solution on YOUR website! . \n" ); document.write( "A man invests his savings in two accounts, one paying 6 percent and the other paying 10 percent simple interest per year. \n" ); document.write( "He puts twice as much in the lower-yielding account because it is less risky. His annual interest is 3960 dollars. \n" ); document.write( "How much did he invest at each rate? \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " The answer in the post by @mananth, 10,000 at 10% and 20,000 at 6%, is incorrect\r \n" ); document.write( "\n" ); document.write( " I came to bring a correct solution.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "investment in 10% --------x \n" ); document.write( "Investment in 6% ----------2x \n" ); document.write( "10%x+6%(2x) = 3960 \n" ); document.write( "multiply by 100 \n" ); document.write( "10x + 12x = 396000 \n" ); document.write( "22x = 396000 \n" ); document.write( "x = 396000/22\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=18000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ANSWER. 18,000 at 10% and 36,000 at 6%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "CHECK. 0.1*18000 + 0.06*(2*18000) = 3960. ! correct !\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solved correctly.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |