document.write( "Question 973570: Hi,\r
\n" ); document.write( "\n" ); document.write( "Well I've run into a problem that I can't really do.\r
\n" ); document.write( "\n" ); document.write( "The question is to rationalise 1/(cube root 2 - 1). The answer is cube root 2 + cube root 4 + 1. I know how to rationalise 1/cube root 2 but I'm not sure how to do this one. What I got is:\r
\n" ); document.write( "\n" ); document.write( "1/cube root 2-1=1/cube root 2-1 * (cube root 2^2 + 1)/(cube root 2^2 + 1)\r
\n" ); document.write( "\n" ); document.write( "And I've so on and so forth, but I didn't get the right answer. I got cube root 4 + 1.\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #853958 by greenestamps(13325)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Use this factoring pattern:

\n" ); document.write( "\"a%5E3-b%5E3=%28a-b%29%28a%5E2%2Bab%2Bb%5E2%29\"

\n" ); document.write( "With \"a=root%283%2C2%29\" and \"b=1\", this becomes

\n" ); document.write( "\"2-1=%28root%283%2C2%29-1%29%28root%283%2C4%29%2Broot%283%2C2%29%2B1%29\"

\n" ); document.write( "Your expression is

\n" ); document.write( "\"1%2Froot%283%2C2%29\"

\n" ); document.write( "To rationalize the denominator, you need to multiply numerator and denominator by

\n" ); document.write( "\"%28root%283%2C4%29%2Broot%283%2C2%29%2B1%29\"

\n" ); document.write( "Then

\n" ); document.write( "

\n" ); document.write( "... which is the answer you say you are supposed to get

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